\(\frac{2.5^{22}-9.5^{21}}{25^{10}}=\frac{2.5^2.5^{20}-9.5.5^{20}}{\left[\left(5\right)^2\right]^{10}}=\frac{5^{20}\left(2.5^2-9.5\right)}{5^{20}}=2.5^2-9.5=5\left(10-9\right)=5.1=5\)
\(\frac{2\cdot5^{22}-9\cdot5^{21}}{25^{10}}=\frac{\left(2\cdot5-9\right)\cdot5^{21}}{25^{10}}=\frac{5^{21}}{5^{20}}=5\)