Ta có: \(\frac{5^2.6^{11}.16^2+6^2.12^6.15^2}{2.6^{12}.10^4-81^2.960^3}\)
\(=\frac{5^2.2^{11}.3^{11}.2^8+2^2.3^2.3^6.2^{12}.5^2.3^5}{2.2^{12}.3^{12}.2^4.5^4-3^8.2^{18}.3^3.5^3}\)
\(=\frac{5^2.2^{19}.3^{11}+3^{13}.2^{14}.5^2}{2^{17}.3^{12}.5^4-2^{18}.3^{11}.5^3}\)
\(=\frac{\left(5^2.2^{14}.3^{11}\right)\left(2^5+3^2\right)}{\left(2^{17}.3^{11}.5^3\right)\left(3.5-2\right)}\)
\(=\frac{\left(2^5+3^2\right)}{\left(2^3.5\right)\left(3.5-2\right)}\)
\(=\frac{32+9}{40.13}\)
\(=\frac{41}{520}\)
\(\frac{5^2.6^{11}.16^2+6^2.12^6.15^2}{2.6^{12}.10^4-81^2.960^3}\)
= \(\frac{5^2.3^{11}.2^{11}.2^8-2^2.3^2.3^6.2^{12}.3^2.5^2}{2.2^{12}.3^{12}.2^4.5^4-3^8.\left(2^6.3.5\right)^3}\)
= \(\frac{5^2.3^{11}.2^{19}-2^{14}.3^{10}.5^2}{2^{17}.3^{12}.5^4-3^8.2^{18}.3^3.5^3}\)
= \(\frac{5^2.3^{10}.2^{14}.\left(3.2^5-1\right)}{2^{17}.3^{12}.5^4-3^{11}.2^{18}.5^3}\)
= \(\frac{5^2.3^{10}.2^{14}.95}{2^{17}.3^{11}.5^3.\left(3.5-2\right)}\)
= \(\frac{5^2.3^{10}.2^{14}.5.19}{2^{17}.3^{11}.5^3.13}\)
= \(\frac{19}{2^3.13}=\frac{19}{104}\)
