Question

Rút gọn biểu thức:

(x^2+2)^2-(x+2)(x-2)(x^2+4)

Hồi nãy mình viết thiếu mong các bạn thông cảm!!!

Answer 1

\(\left(x^2\right)^2-\left(x+2\right)\left(x-2\right)\left(x^2+4\right)\)

\(=\left(x^2\right)^2-\left(x^2-4\right)\left(x^2+4\right)\)

\(=x^4-\left(x^4-16\right)\)

\(=x^4-x^4+16=16\)

Answer 2

\(=\left(x^2\right)^2-\left(x^2-14\right)\left(x^2+4\right)\)

\(=x^4-x^4+16\)

\(=16\)

Answer 3

\(\left(x^2\right)^2-\left(x+2\right)\left(x-2\right)\left(x^2+4\right)\)

\(=x^4-\left(x^2-4\right)\left(x^2+4\right)\)

\(=x^4-\left(x^4-16\right)=16\)

Answer 4

Thử, sai bỏ qua:

\(\left(x^2\right)^2-\left(x+2\right)\left(x-2\right)\left(x^2+4\right)\)

\(=x^4-\left(x^2-4\right)\left(x^2+4\right)\)

\(=x^4-\left(x^4-16\right)\)

\(=x^4-x^4+16\)( bỏ ngoặc )

\(=16\)

~ Rất vui vì giúp đc bn ~

Answer 5

\(= x^4 - ( x^2 - 4 ) (x^2 + 4 )\)

\(= x^4 - ( x^4 - 16 )\)

\(= x^4 - x^4 + 16 ( phá ngoặc )\)

\(= 16\)

\(#Sói#\)