dùm hằng đẳng thức nhanh hơn nguyen thieu cong thanh
\(\frac{x^2-1}{x+1}=\frac{x^2+x-x-1}{x+1}=\frac{x^2+x-\left(x+1\right)}{x+1}=\frac{x\left(x+1\right)-\left(x+1\right)}{x+1}\)
\(=\frac{\left(x-1\right)\left(x+1\right)}{x+1}=x-1\)
vậy \(\frac{x^2-1}{x+1}=x-1\)