\(B=(1+\frac{1}{1.3})(1+\frac{1}{2.4})(1+\frac{1}{3.5})...(1+\frac{1}{\text{2015.2017}})\)
\(\text{B=}\frac{\text{2.2.3.3.4.4....2016.2016}}{\text{3.8.15....4064255}}\)
\(B=\frac{\text{2.2.3.3.4.4....2016.2016}}{\text{1.3.2.4.3.5.....2015.2017}}\)
\(B=\frac{\text{2.3.4....2016}}{\text{1.2.3.....2015}}.\frac{\text{2.3.4.....2016}}{\text{3.4.5.....2017}}\)
\(B=2016.\frac{2}{2017}\)
\(B=\frac{2016.2}{2017}\)
\(B=\frac{4032}{2017}\)
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