x2 + 8x - 20 = x2 + 10x - 2x - 20 = x(x+10) - 2(x+10) = (x - 2)(x+ 10)
|x - 2| = x - 2 nếu x > 2; |x - 2| = -(x - 2) = - x + 2 nếu x < 2
Vậy A = \(\frac{x\left(x-2\right)}{\left(x-2\right)\left(x+10\right)}=\frac{x}{x+10}\) nếu x > 2
A = \(\frac{-x\left(x-2\right)}{\left(x-2\right)\left(x+10\right)}=\frac{-x}{x+10}\) nếu x < 2
A=(x/x-2/)/x^2+8x-20=(x/x-2/)/(x-2).(x+10)
TH1:x>=2
A=x.(x-2)/(x-2).(x+10)=x/x+10
TH2:x<2
A=(-x).(x-2)/(x-2).(x+10)=-x/x+10