Question

Rút gọn :

A = \(\frac{4157-19}{12471-57}\)

B = \(\frac{7}{10^2+8.10^2}\)

C = \(\frac{31995}{42660-108}\)

D = \(\frac{2^{45}.5^3.2^6.3}{8.2^{18}.81.5}\)

Ai làm đầy đủ , chi tiết , tui tk 10 lần .

Nhanh lên nhé ! 1h tui đi học rùi !

Answer 1

\(A=\frac{4157-19}{12471-57}\)\(=\frac{4138}{12414}\)\(=\frac{4138:4138}{12414:4138}\)\(=\frac{1}{3}\)

\(B=\frac{7}{10^2+8.10^2}\)\(=\frac{7}{100+8.100}\)\(=\frac{7}{100+800}\)\(=\frac{7}{900}\)

\(C=\frac{31995}{42660-108}\)\(=\frac{31995}{42552}\)\(=\frac{31995:27}{42552:27}\)\(=\frac{1185}{1576}\)

\(D=\frac{2^{45}.5^3.2^6.3}{8.2^{18}.81.5}=\frac{2^{51}.5^3.3}{2^3.2^{18}.3^4.5}=\frac{2^{51}.5^3.3}{2^{21}.3^4.5}=\frac{2^{30}.5^2}{3^3}\)

k mình nhé.

Answer 2

A=4138/12414=1/3

B=7/900

C=31995/42552=1185/1576

Phần D tui chịu, ahihi