A = \(1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2015}}\)
2A = \(2+1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2014}}\)
2A - A =\(2+1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2014}}\)\(-\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2015}}\right)\)
A = \(2-\frac{1}{2^{2015}}\)
Katherine Lilly Filbert trả lời đúng rồi đấy