Câu hỏi của bang gia

Question

R=22010-[22009+22008+...+21+20)

dung ơi i love you · Accepted Answer

$R=2^{2010}-\left[2^{2009}+2^{2008}+...+2^1+2^0\right]$$2^{2010}-R=2^0+2^1+...+2^{2008}+2^{2009}$$2^{2011}-2R=2^1+2^2+...+2^{2009}+2^{2010}$$\left(2^{2011}-2R\right)-\left(2^{2010}-R\right)=2^{2010}-1$$2^{2010}-R=2^{2010}-1$$R=2^{2010}-2^{2010}+1=0+1=1$Câu trả lời: $R=2^{2010}-\left[2^{2009}+2^{2008}+...+2^1+2^0\right]$$2^{2010}-R=2^0+2^1+...+2^{2008}+2^{2009}$$2^{2011}-2R=2^1+2^2+...+2^{2009}+2^{2010}$$\left(2^{2011}-2R\right)-\left(2^{2010}-R\right)=2^{2010}-1$$2^{2010}-R=2^{2010}-1$$R=2^{2010}-2^{2010}+1=0+1=1$

bang gia · Answer

ban lam co dung koCâu trả lời: ban lam co dung ko

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