Vận tốc cano đi xuôi dòng là:
\(V_{xd}=\frac{S}{t}=\frac{80}{4}=20\) (km/h)
Vận tốc khi đi ngược dòng là:
\(V_{nd}=\frac{S}{t}=\frac{80}{5}=16\) (km/h)
Vận tốc dòng nước là
\(\frac{20-16}{2}=2\) (km/h)
Vận tốc thực của cano là
\(20-2=18\) (km/h)
Ủng hộ cho mình nha bạn
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