Question

q bằng1+3+3mũ2+3mũ3+3mũ4+...+3mũ11:52

Mọi người ơi giải hộ mk nhé

Answer 1

3 mũ 11:52 là số nào vậy bạn

Answer 2

\(Q=1+3+3^2+3^3+3^4+...+3^{11}\)

\(3Q=3+3^2+3^3+3^4+3^5+...+3^{12}\)

\(3Q-Q=\left(3+3^2+3^3+3^4+3^5+...+3^{12}\right)-\left(1+3+3^2+3^3+3^4+...+3^{11}\right)\)

\(2Q=3^{12}-1\)

\(Q=\frac{3^{12}-1}{2}\)

Answer 3

Sai rroif mk tưởng tính Q

Answer 4

\(Q=1+3+3^2+...+3^{11}=\left(1+3\right)+\left(3^2+3^3\right)+...+\left(3^{10}+3^{11}\right)\)

\(Q=4+4\cdot3^2+4\cdot3^4+...+4\cdot3^{10}⋮4\)

Lại có \(Q=1+3+3^2+...+3^{11}=\left(1+3+3^2\right)+\left(3^3+3^4+3^5\right)+...+\left(3^9+3^{10}+3^{11}\right)\)

\(Q=\left(1+3+3^2\right)\left(1+3^3+...+3^9\right)=13k⋮13\)

Vì \(\left(13,4\right)=1\Rightarrow Q⋮52\)

Chúc bạn học tốt!