Question

phân tích đt thành nt

a, x²-7x+12

b,3x²+13x-10

c,x²- 2x-3

d,x^2+3x-18

Answer 1

\(x^2-7x+12=x^2-3x-4x+12=x\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x-4\right)\)

\(x^2-2x-3=x^2+x-3x-3=x\left(x+1\right)-3\left(x+1\right)=\left(x+1\right)\left(x-3\right)\)

\(x^2+3x-18=x^2-3x+6x-18=x\left(x-3\right)+6\left(x-3\right)=\left(x-3\right)\left(x+6\right)\)

Answer 2

a,x²-7x+12=(x-4)(x-3)

b,3x²+13x-10=(3x-2)(x+5)

c,x²-2x-3=(x-3)(x+1)

d,x²+3x-18=(x-3)(x+6)

Answer 3

a. \(x^2-7x+12=x^2-3x-4x+12=x\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x-4\right)\)

b. \(3x^2+13x-10=3x^2+15x-2x-10=3x\left(x+5\right)-2\left(x+5\right)=\left(x+5\right)\left(3x-2\right)\)

c. \(x^2-2x-3=x^2+x-3x-3=x\left(x+1\right)-3\left(x+1\right)=\left(x+1\right)\left(x-3\right)\)