Question

Phân tích đa thức thành nhân tử

x^4+x^3y-xy^3-y^4

Answer 1

\(x^4+x^3y-xy^3-y^4=x^3\left(x+y\right)-y^3\left(x+y\right)\)

\(=\left(x+y\right)\left(x^3-y^3\right)=\left(x+y\right)\left(x-y\right)\left(x^2+xy+y^2\right)\)

Answer 2

\(x^4+x^3y-xy^3-y^4\)

\(=x^3.\left(x+y\right)-y^3.\left(x+y\right)\)

\(=\left(x^3-y^3\right).\left(x+y\right)\)