x3+y3+z3-3xyz
= (x+y)3-3xy(x+y)+z3-3xyz
= [(x+y)3+z3]-[3xy(x+y)+3xyz]
=(x+y+z)[(x+y)2-(x+y).z+z2]-3xy(x+y+z)
=(x+y+z)(x2+y2+z2+2xy-xz-yz) -3xy(x+y+z)
= (x+y+z)(x2+y2+z2-xy-xz-yz)
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