Question

Phân tích đa thức thành nhân tử

mx² - 4mx + 4m - nx² + 4nx - 4n

Answer 1

\(mx^2-4mx+4m-nx^2+4nx-4n\)

\(=\left(mx^2-4mx+4m\right)-\left(nx^2-4nx+4n\right)\)

\(=m\left(x^2-4x+4\right)-n\left(x^2-4x+4\right)\)

\(=\left(m-n\right)\left(x^2-4x+4\right)\)

\(=\left(m-n\right)\left(x-2\right)^2\)

Answer 2

\(mx^2-4mx+4m-nx^2+4nx-4n\)

\(=x^2\left(m-n\right)+4x\left(n-m\right)+4\left(m-n\right)\)

\(=x^2\left(m-n\right)-4x\left(m-n\right)+4\left(m-n\right)\)

\(=\left(x^2-4x+4\right)\left(m-n\right)\)

\(=\left(x-2\right)^2\left(m-n\right)\)