Question

phân tích đa thức thành nhân tử

\(a^2-10a+25-y^2-4yz-4z^2\)

Answer 1

       \(a^2-10a+25-y^2-4yz-4z^2\)

\(=a^2-2.a.5+5^2-y^2-2.y.2z-\left(2z\right)^2\)

\(=\left(a-5\right)^2-\left(y+2z\right)^2\)

\(=\left(a-y-2z-5\right)\left(a+y+2z-5\right)\)

Answer 2

Very easy

\(a^2-10a+25-y^2-4yz-4z^2\)

\(=\left(a-5\right)^2-\left(y+2z\right)^2\)

\(=\left(a-5-y-2z\right)\left(a-5+y+2z\right)\)