Hướng dẫn thôi :
a) x ( x + 2 ) ( x^2 - 6x + 4 )
b) ( x + 1 ) ( x + 2 ) ( x - 2 )
b) x^3 + x^2 - 4x - 4
= x^2 ( x + 1 ) - 4 ( x + 1 )
= ( x + 1 ) ( x^2 - 2^2 )
= ( x + 1 ) ( x + 2 ) ( x - 2)
\(x^4-4x^3-8x^2+8x\)
\(=x\left(x^3-4x^2-8x+8\right)\)
\(=x.\left[\left(x^3+2x^2\right)-\left(6x^2+12x\right)+\left(4x+8\right)\right]\)
\(=x.\left[x^2.\left(x+2\right)-6x\left(x+2\right)+4.\left(x+2\right)\right]\)
\(=x.\left(x+2\right)\left(x^2-6x+4\right)\)
Tham khảo nhé~
\(x^3+x^2-4x-4\)
\(=x^2\left(x+1\right)-4\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2-4\right)\)
\(=\left(x+1\right)\left(x-2\right)\left(x+2\right)\)
