Question

Phân tích đa thức thành nhân tử:

1) x² - 4 + ( x-2)²

2) x³ - 6x² + 9x

3) x² -2xy + y² -a² + 4ab - 4²

4) x⁴ + 4

5) 4a²(a-2b) - 10a(2b - a)

6) 3x² - y² + 4x -2xy +1

Answer 1

1) =(x+2)(x-2)+(x-2)²=(x-2)(x+2+x-2)=2x(x+2)

2)=x(x²-6x+9)=x(x-3)²

3)xem lại đề giúp mik

4)=x⁴+4x²-4x²+4=(x⁴+4x²+4)-4x²=(x²+2)²-4x²=(x²+2x+2)(x²-2x+2)

Answer 2

\(x^2-4+\left(x-2\right)^2\)

\(=\left(x-2\right)\left(x+2\right)+\left(x-2\right)^2\)

\(=\left(x-2\right)\left(x+2+x-2\right)\)

\(=2x\left(x-2\right)\)

Answer 3

5) \(4a^2\left(a-2b\right)-10a\left(2b-a\right)\)

\(=4a^2\left(a-2b\right)+10a\left(a-2b\right)\)

\(=\left(4a^2+10a\right)\left(a-2b\right)\)

\(=a\left(4a+10\right)\left(a-2b\right)\)

6) \(3x^2-y^2+4x-2xy+1\)

\(=\left[-\left(y-x-1\right)\right]\left(y+3x+1\right)\)