Question

Phan tich da thuc thanh nhan tu.                  x^8+x^7+1.                                                        x^7+x^2+1

Answer 1

a)x^8 + x^7 +1

= x^8 - x^2 + x^7 - x + x^2+x +1

= x^2(x^6-1) + x(x^6-1) +x^2+x+1

= (x^6-1)(x^2+x) + x^2+x+1

=(x^3-1)(x^3+1)(x^2+x)+x^2+x+1

=(x-1)(x^2+x+1)(x^3+1)(x^2+x)+x^2+x+1

=(x^2+x+1)( x^6 +x^3-x^4-x+1)

b) tương tự

Answer 2

a)x^8 + x^7 +1

= x^8 - x^2 + x^7 - x + x^2+x +1

= x^2(x^6-1) + x(x^6-1) +x^2+x+1

= (x^6-1)(x^2+x) + x^2+x+1

=(x^3-1)(x^3+1)(x^2+x)+x^2+x+1

=(x-1)(x^2+x+1)(x^3+1)(x^2+x)+x^2+x+1

=(x^2+x+1)( x^6 +x^3-x^4-x+1)

Answer 3

a)x^8 + x^7 +1

= x^8 - x^2 + x^7 - x + x^2+x +1

= x^2(x^6-1) + x(x^6-1) +x^2+x+1

= (x^6-1)(x^2+x) + x^2+x+1

=(x^3-1)(x^3+1)(x^2+x)+x^2+x+1

=(x-1)(x^2+x+1)(x^3+1)(x^2+x)+x^2+x+1

=(x^2+x+1)( x^6 +x^3-x^4-x+1)

Answer 4

x^8 + x^7 + 1

= x^8 - x^2 + x ^7 + x^2 + x + 1

=  x^2(x^6-1)+x(x^6-1)+x^2+x^1

= (x^6 - 1)(x^2+x)+x^2+x1

=(x^3 - 1)(x^3+1)(x^2+x)+x^2+x+1

=(x-1)(x^2+x+1)(x^3+1)(x^2+x)+x^2 + x + 1

= (x^2+x+1)(x^6+x^3-x^4-x+1)

Answer 5

x^8 + x^7 + 1

= x^8 - x^2 + x ^7 + x^2 + x + 1

=  x^2(x^6-1)+x(x^6-1)+x^2+x^1

= (x^6 - 1)(x^2+x)+x^2+x1

=(x^3 - 1)(x^3+1)(x^2+x)+x^2+x+1

=(x-1)(x^2+x+1)(x^3+1)(x^2+x)+x^2 + x + 1

= (x^2+x+1)(x^6+x^3-x^4-x+1)

Answer 6

a)x^8 + x^7 +1

= x^8 - x^2 + x^7 - x + x^2+x +1

= x^2(x^6-1) + x(x^6-1) +x^2+x+1

= (x^6-1)(x^2+x) + x^2+x+1

=(x^3-1)(x^3+1)(x^2+x)+x^2+x+1

=(x-1)(x^2+x+1)(x^3+1)(x^2+x)+x^2+x+1

=(x^2+x+1)( x^6 +x^3-x^4-x+1)