Question

Phân tích đa thức thành nhân tử   x⁷y+x⁵y+x³y

Answer 1

A=x^3y(x^4+x^2+1)

Hết

Answer 2

x⁷y+x⁵y+x³y=x³y.(x⁴+x²+1)

=x³y.(x⁴+2x²+1-x²)

=x³y.[(x²+1)²-x²]

=x³y.(x²-x+1)(x²+x+1)

 

Answer 3

\(=x^3y\left(x^4+x^2+1\right)\)

\(=x^3y\left(x^4+2x^2+1-x^2\right)\)

\(=x^3y\left[\left(x^2+1\right)-x^2\right]\)

\(=x^3y\left(x^2-x+1\right)\left(x^2+x+1\right)\)