Question

phân tích đa thức thành nhân tử

\(x^5+x^4+1\)

Answer 1

\(x^5+x^4+1=\left(x^5+x^4+x^3\right)-\left(x^3-1\right)\)

\(=x^3\left(x^2+x+1\right)-\left(x-1\right)\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^3-x+1\right)\)

Answer 2

Lời giải:

\(x^5+x^4+1=x^3(x^2+x+1)-x^3+1\)

\(=x^3(x^2+x+1)-(x^3-1)=x^3(x^2+x+1)-(x-1)(x^2+x+1)\)

\(=(x^2+x+1)[x^3-(x-1)]\)

\(=(x^2+x+1)(x^3-x+1)\)