Question

phân tích đa thức thành nhân tử :
\(x^4+x^3+x^2-1\)

Answer 1

\(x^4+x^3+x^2-1\)

\(=x^3\left(x+1\right)+\left(x+1\right)\left(x-1\right)\)

\(=\left(x+1\right)\left(x^3+\left(x-1\right)\right)\)

Ủng hộ nha ^ _ ^

Answer 2

\(x^4+x^3+x^2-1\)

\(=x^2\left(x^2-1\right)+x^2-1\)

\(=\left(x^2+1\right)\left(x^2-1\right)\)

Answer 3

\(x^4+x^3+x^2-1=\left(x^4+x^3\right)+\left(x^2-1\right)=x^3\cdot\left(x+1\right)+\left(x+1\right)\cdot\left(x-1\right)\)\(=\left(x+1\right)\cdot\left(x^3+x-1\right)\)

Answer 4

\(x^4+x^3+x^2-1\)

\(x\left(x^3+x^2+x\right)-1\)=\(x\left(x^3+x^2+x-1\right)\)

Không bik đúng hay sai bik mới học thông cảm

Answer 5

\(x^4+x^3+x^2-1\)

\(=x^3\left(x+1\right)+\left(x+1\right)\left(x-1\right)\)

\(=\left(x+1\right)\left(x^3+\left(x-1\right)\right)\)

Answer 6

\(x^4+x^3+x^2-1\)

\(=x^3.\left(x+1\right)+\left(x+1\right)\left(x-1\right)\)

\(=\left(x+1\right)\left[x^3+\left(x-1\right)\right]\)

~ Rất vui vì gíup đc bn ~

Answer 7

\(x^4+x^3+x^2-1\)

\(=x^3\left(x+1\right)+\left(x-1\right)\left(x+1\right)\)

\(=\left(x^3+x-1\right)\left(x+1\right)\)

Answer 8

\(x^4+x^3+x^2-1=x^3\left(x+1\right)+\left(x-1\right)\left(x+1\right)\)

                                     \(=\left(x+1\right)\left(x^3+x-1\right)\)