Question

phân tích đa thức thành nhân tử :

x^3-1+5x^2-5+3x-3 

 

Answer 1

\(x^3+5x^2+3x-9=x^2\left(x+5\right)\\ +3\left(x-3\right)\)

Answer 2

        \(x^3-1+5x^2-5+3x-3\)

\(=\left(x-1\right)\left(x^2+x+1\right)+5\left(x^2-1\right)+3\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+x+1\right)+5\left(x-1\right)\left(x+1\right)+3\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+x+1\right)+\left(5x+5\right)\left(x-1\right)+3\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+x+1+5x+5+3\right)\)

\(=\left(x-1\right)\left(x^2+6x+9\right)=\left(x-1\right)\left(x+3\right)^2\)

Chúc bạn học tốt.

Answer 3

x − 1 + 5x − 5 + 3x − 3

= x − 1 x + x + 1 + 5 x − 1 + 3 x − 1

= x − 1 x + x + 1 + 5 x − 1 x + 1 + 3 x − 1

= x − 1 x + x + 1 + 5x + 5 x − 1 + 3 x − 1

= x − 1 x + x + 1 + 5x + 5 + 3

= x − 1 x + 6x + 9 =

x − 1 x +3