Question

Phân tích đa thức thành nhân tử ( nhóm nhiều hạng tử )
a) ax - 2x - a² + 2a
b) x² + x - ax - a 
c) 2x² + 4ax + x + 2a 

d) 2xy - ax + x² - 2ay

Answer 1

a) ax - 2x - a² + 2a

= ( ax - 2x ) - ( a² - 2a )

= x ( a - 2 ) - a ( a - 2 )

= ( a - 2 ) ( x - a )

b) x² + x - ax - a

= ( x² + x ) - ( ax + a )

= x ( x + 1 ) - a ( x + 1 )

= ( x + 1 ) ( x - a )

Hok Tốt!!!

Answer 2

a) ax -2x- a²+ 2a

= (ax -2x ) -(a² -2a )

= x(a-2) -a ( a-2 )

= (x-a) (a-2)

b) x² +x -ax -a

=( x² +x ) - ( ax +a )

= x( x+1 ) -a ( x+1 )

= ( x-a ) (x+ 1)

c) 2x² +4ax +x +2a

=( 2x² + 4ax )  + ( x+ 2a )

= 2x ( x+ 2a ) + ( x+2a )

= ( 2x +1 ) (x+2a )

d) 2xy -ax +x² - 2ay

= (2xy -2ay ) + (  -ax + x² )

= 2y( x-a ) + x ( x-a)

= ( 2y +x ) ( x -a )

Answer 3

a)  \(ax-2x-a^2+2a=\left(ax-2x\right)-\left(a^2-2a\right)\)

\(=x\left(a-2\right)-a\left(a-2\right)=\left(x-a\right)\left(a-2\right)\)

b)    \(x^2+x-ax-a=\left(x^2+x\right)-\left(ax+a\right)\)

\(=x\left(x+1\right)-a\left(x+1\right)=\left(x-a\right)\left(x+1\right)\)

c) \(2x^2+4ax+x+2a=\left(2x^2+x\right)+\left(4ax+2a\right)\)

\(=x\left(2x+1\right)+2a\left(2x+1\right)=\left(x+2a\right)\left(2x+1\right)\)

d)  \(2xy-ax+x^2-2ay=\left(2xy-2ay\right)+\left(x^2-ax\right)\)

\(=2y\left(x-a\right)+x\left(x-a\right)=\left(2y-x\right)\left(x-a\right)\)

Hok tốt