Question

Phân tích đa thức thành nhân tử: 3x² - 6xy + 3y² - 12z²

Answer 1

\(3x^2-6xy+3y^2-12z^2\)

\(=3\left(x^2-2xy+y^2-4z^2\right)\)

\(=3\left[\left(x-y\right)^2-4z^2\right]=3\left(x-y-2z\right)\left(x-y+2z\right)\)

Answer 2

Ta có: \(3x^2-6xy+3y^2-12z^2\)

    \(=3.\left(x^2-2xy+y^2-4z^2\right)\)

    \(=3.\left[\left(x-y\right)^2-4z^2\right]\)

    \(=3.\left(x-y-2z\right).\left(x-y+2z\right)\)

Answer 3

3x² - 6xy + 3y² - 12z²

= 3( x² - 2xy + y² - 4z² )

= 3[ ( x - y )² - ( 2z )² ]

= 3( x - y - 2z )( x - y + 2z )