Question

Phân tích đa thức thành nhân tử: (12x^2-12xy+3y^2)-10(2x-y)+8

Answer 1

(12x^2 - 12xy + 3y^2) - 10.(2x - y) + 8 

= 3(4x^2 - 4xy + y^2) - 10(2x - y) + 8 

= 3(2x - y)^2 - 10(2x - y) + 8 

= 3(2x - y)^2 - 10(2x - y) + 8 

= 3(2x - y)^2 - 6(2x - y) - 4(2x - y) + 8 

= 3(2x - y)(2x - y - 2) - 4(2x - y -2) 

= (2x - y -2)[3(2x - y) - 4] 

= (2x - y -2)(6x - 3y -4)

Ai k mk mk k lại

Answer 2

(12x^2 - 12xy + 3y^2) - 10.(2x - y) + 8 
= 3(4x^2 - 4xy + y^2) - 10(2x - y) + 8 
= 3(2x - y)^2 - 10(2x - y) + 8 
= 3(2x - y)^2 - 10(2x - y) + 8 
= 3(2x - y)^2 - 6(2x - y) - 4(2x - y) + 8 
= 3(2x - y)(2x - y - 2) - 4(2x - y -2) 
= (2x - y -2)[3(2x - y) - 4] 
= (2x - y -2)(6x - 3y -4)