Question

Phân tích đa thức sau thành nhân tử:

a^3m+2a^2m+a^m

Answer 1

a^3m+2a^2m+a^m = a^m(a^2m+2a^m+1) = a^m[(a^m)²+2a^m+1] = a^m(a^m+1)²

Answer 2

Ta có :

a^3m+2a^2m+a^m 

= a^m(a^2m+2a^m+1)

= a^m[(a^m)²+2a^m+1]

= a^m(a^m+1)²

Answer 3

\(a^{3m}+2a^{2m}+a^m\)

\(\Leftrightarrow a^m\left(a^{2m}+2a^m+1\right)\)

\(\Leftrightarrow a^m\left[\left(a^m\right)^2+2a^m+1\right]\)

\(\Leftrightarrow a^m\left(a^m+1\right)^2\)

\(\Leftrightarrow a^m\left(a^m+1\right)\left(a^m+1\right)\)