Question

Phân tích đa thức sau thành nhân tử :
a)\(x^3-2x^2+x\)                       c)\(5x^2y^3-25x^3y^4+10x^3y^3\)                  e)\(36-12x+x^2\)

b)\(x^2-2x-15\)                   d)\(12x^2y-18xy^2-30y^2\)                        g)\(11x+11y-x^2-xy\)

                                                             CÁC BẠN GIÚP MÌNH NHA <3

 

Answer 1

mình cũng bạch dương nè

Answer 2

a) x³   -   2x² + x = x(x²  - 2x + x )=x(x² + x)

Answer 3

\(x^3-2x^2+x=x^3-x^2-x^2+x\)

\(=\left(x^3-x^2\right)-\left(x^2-x\right)\)

\(=x^2\left(x-1\right)-x\left(x-1\right)\)

\(=\left(x^2-x\right)\left(x-1\right)\)

\(e,36-12x+x^2=6^2-2.6x+x^2\)

\(=\left(6-x\right)^2\)

\(g,11x+11y-x^2-xy=\left(11x+11y\right)-\left(x^2+xy\right)\)

\(=11\left(x+y\right)-x\left(x+y\right)\)

\(=\left(11-x\right)\left(x+y\right)\)

Answer 4

c) 5x²y³   - 25x³y⁴  + 10x³y³    = 5x²y³ (1 - 5xy + 2x)

Answer 5

\(a,x^3-2x^2+x=x^3-x^2-x^2+x\)

\(=x^2\left(x+1\right)-x\left(x+1\right)=\left(x+1\right)\left(x^2-x\right)\)

\(=\left(x+1\right)x\left(x-1\right)\)

\(b,x^2-2x-15=x^2-5x+3x-15\)

\(=x\left(x-5\right)+3\left(x-5\right)=\left(x-5\right)\left(x+3\right)\)

\(c,5x^2y^3-25x^3y^4+10x^3y^3=5x^2y^3\left(-5xy+2x\right)\)

\(=5x^2y^3.x\left(-5y+2\right)=5x^3y^3\left(2-5y\right)\)

\(d,12x^2y-18xy^2-30y^2=6y\left(2x^2-3xy-5y\right)\)

\(e,36-12x+x^2=x^2-12x+36=x^2-2.x.6+6^2\)

                                \(=\left(x-6\right)^2\)

\(g,11x+11y-x^2-xy=11\left(x+y\right)-x\left(x+y\right)\)

\(=\left(x+y\right)\left(11-x\right)\)

Answer 6

a)\(x^3-2x^2+x\)

\(=x.\left(x^2-2x+1\right)\)

\(=x.\left(x-1\right)^2\)

b)\(x^2-2x-15\)

\(=x^2+3x-5x-15\)

\(=x.\left(x+3\right)-5.\left(x+3\right)\)

\(=\left(x+3\right).\left(x-5\right)\)

c)\(5x^2y^3-25x^3y^4+10x^3y^3\)

\(=5x^2y^3.\left(1-5xy+2x\right)\)

d)\(12x^2y-18xy^2-30y^2\)

\(=6y.\left(2x^2-3xy-5y\right)\)

e)\(36-12x+x^2\)

\(=6^2-12xx+x^2\)

\(=\left(6-x\right)^2\)

g)\(11x+11y-x^2-xy\)

\(=11.\left(x+y\right)-x.\left(x+y\right)\)

\(=\left(x+y\right).\left(11-x\right)\)