Question

Phân tích đa thức sau thành nhân tử :

a/ \(x^2+x+6\)

b/ \(3x^2+2x-5\)

c,\(3-2x-x^2\)

d,\(x^2+7x+12\)

e,\(x^2-x-12\)

f,\(x^2+x+12\)

Ai nhanh mình sẽ vote cho bạn đó ạ

Answer 1

b) \(3x^2+2x-5=3\left(x-1\right)\left(x+\dfrac{5}{3}\right)\)

c) \(3-2x-x^2=-\left(x-1\right)\left(x+3\right)\)

d) \(x^2+7x+12=\left(x+3\right)\left(x+4\right)\)

e) \(x^2-x-12=\left(x-4\right)\left(x+3\right)\)

 

Answer 2

b: \(3x^2+2x-5\)

\(=3x^2-3x+5x-5\)

\(=\left(x-1\right)\left(3x+5\right)\)

c: \(3-2x-x^2\)

\(=-\left(x^2+2x-3\right)\)

\(=-\left(x+3\right)\left(x-1\right)\)

d: \(x^2+7x+12=\left(x+3\right)\left(x+4\right)\)

e: \(x^2-x-12=\left(x-4\right)\left(x+3\right)\)