Question

phân tích đa thức sau thành nhân tử 

27x^3-0,001

a^4-2a^2+1

(a^2+4)^2-16a^2

 

Answer 1

a) \(27x^3-0,001\)

\(=\left(3x\right)^3-\left(\frac{1}{10}\right)^3\)

\(=\left(3x-\frac{1}{10}\right)\left(9x^2+\frac{3}{10}x+\frac{1}{100}\right)\)

b) \(a^4-2a^2+1\)

\(=\left(a^2\right)^2-2a^2+1\)

\(=\left(a^2-1\right)^2\)

c)\(\left(a^2+4\right)^2-16a^2\) 

\(=\left(a^2+4\right)^2-\left(4a\right)^2\)

\(=\left(a^2+4-4a\right)\left(a^2+4+4a\right)\)

\(=\left(a-2\right)^2\left(a+2\right)^2\)