n.(2x-5)2=9
(2x-5)2=32
* 2x-5=3 * 2x-5=-3
2x=3+5 2x=-3+5
2x=8 2x=2
x=8:2 x=2:2
x=4 x=1
vậy x=4 hoặc x=1
o.(1-3x )3=-8
(1-3x)3=(-2)3
1-3x=-2
3x=1-(-2)
3x=3
x=3:3
x=1
vậy x=1
n.(2x-5)2=9
(2x-5)2=32
* 2x-5=3 * 2x-5=-3
2x=3+5 2x=-3+5
2x=8 2x=2
x=8:2 x=2:2
x=4 x=1
vậy x=4 hoặc x=1
o.(1-3x )3=-8
(1-3x)3=(-2)3
1-3x=-2
3x=1-(-2)
3x=3
x=3:3
x=1
vậy x=1
Tìm x thuộc Z;
a) 12+11+10+....+(x+1)+x =-13
b) x+(x+1)+(x+2)+....+2008+2009=2009
c) 196 +1962+....+(x+1)+x=3925
d) -12 (x-5)+7 (3-x)=5
e) 2 (x-3) - 3 (2-3x)=4 [(1-2x)+15]
f) 3 (x-1) - (x-5) = -15
g) 5 (x-2) - ( x+3)+15
h) /x+1/=a (a thuộc Z)
Giúp mình nhé mình đang gấp lắm. Cảm ơn rất nhiều
e) ( x + 3)^3 = ( 2x) ^3
f) ( 5 - x )^5 = 32
g) ( 5x - 6)^3 = 64
h)5 . 9^x = 405
i) 11^5 : 11^ n - 2 = 11^5
k) ( 3x)^3 = ( 2x + 1)^3
A) 78-2x=42
B)6x+39=75
C) 2^3.x+ 2.x=25.2^2
D) 21+7x = 56
E) 5x +2x = 6^2-5^0
F)15x + 3x = 450 : 2+9
G) 6x+x=5^11: 5^9+3^1
H) 5x + 3x=3^11: 3^8.4+12
i) 2^3.x + 2^2.x =136-2^20 : 2^16
j) 7x -x= 5^21: 5^19+3.2^2
k) 7x - 2x= 6^17: 6^15 + 44 :11
l) 0: x =0 m) 3^x=27 n) 4^x= 64
o) 2^x = 32 p) 9^x-1=81 q) x^4=16
r) 3^x :3^
p) 9^x-1=81
q) x^4=165=1
Bài 1:
a)-2x-3.( x-17 )= 34-2.( -x+25 )
b)17x+3.( -16x-37 )= 2x+43-4x
c){-3x+2. [ 45-x-3 ( 3x+7 ) -2x]+4x} = 55
g)-103-57: [ 5.( 2x-1 )2-( -9 )0 ]
Bài 2:
a)-5.( -x+7 )-3.( -x-5 )=-4.( 12-x )+48
b)7.( -x-7 )-4.( -2x-11 )=7.( 4x+10 )+9
c)-2.( 15-3x )-4.( -7x+8 )=-5-9.( -2x+1 )
d)5.( -3x-7 )-4.( -2x-11 )=7.( 4x+10 )+9
e)4( x-2 )2-13=( -3 )2.2-11.( -3 )
f)-52-( 2x-1 )3=( -13 ).( -3 )
tìm x, biết x thuộc Z
(x+2).(x-5)=0
(2x+9)2=0
(2x-1)3=8
(1-3x)2=16
(3x+1)+1=-26
(x+1)+(x+3)+(x+5)+...+(x+2017)=0
(x-3).(x-2)+(x-1)+...+10+11=11
(x+3).(x2+1)=0
làm giúp mình với,cảm ơn
I,1,Tìm giá trị nhỏ nhất
D=|x-2|+|x-9|+|x+1945|
II,Tìm x,y,z
1,|x-2|-|2x+3|-x=2 2,|x-2|-|2x-3|-x=2
3,|x-7|+2x+5=6 4,$\left(3x-5\right)^{2006}+\left(y^2-1\right)^{2008}+\left(x-2\right)^{2100}=0$(3x−5)2006+(y2−1)2008+(x−2)2100=0
5,||x+3|-11|=2 6,2009-|x-2009|=x
Tìm x
a) (x + 1) phần 2009 + (x + 2) phần 2008 + (x + 3 )phần 2007 = -3
b) (x + 1) phần 2009 + (x + 2) phần 2008 = (x + 10) phần 2000 + (x + 11) phần 1999
tìm x
a) \(\frac{x-1}{2}+\frac{x-2}{5}=\frac{1}{4}+\frac{x-7}{10}\)
b) \(3-\frac{2}{2x-3}=\frac{2}{5}+\frac{1}{2x-3}-\frac{3}{2}\)
c)\(7\cdot\left(x-1\right)+2x\cdot\left(1-x\right)=0\)
d) \(\frac{x+1}{2008}+\frac{x+2}{2017}+\frac{x+3}{2016}=\frac{x+10}{2009}+\frac{x+11}{2008}+\frac{x+12}{2007}\)
e) \(\frac{2}{\left(x-1\right)\cdot\left(x-3\right)}+\frac{5}{\left(x-3\right)\cdot\left(x-8\right)}+\frac{12}{\left(x-8\right)\cdot\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)