Question

N = \(\frac{3}{5.7}+\frac{3}{7.9}+\frac{3}{9.11}+...+\frac{3}{197.199}\)

(nhớ có lời giải nhé)

Answer 1

N=\(3.\left(\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{197.199}\right)\)

N=\(\frac{3}{2}.\left(\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{197.199}\right)\)

N=\(\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{197}-\frac{1}{199}\right)\)

N=\(\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{999}\right)\)

N=\(\frac{3}{2}.\frac{194}{995}\)

N=\(\frac{291}{995}\)

Answer 2

= 3/5-3/7+3/7-3/9+3/9-3/11+......+3/197-3/199

= 3/5-3/199

= 582/995