bạn đăng tách ra nhé
a, \(=x\left(3y+1\right)+5\left(3y+1\right)=\left(x+5\right)\left(3y+1\right)\)
b, \(=9-\left(x-y\right)^2=\left(3-x+y\right)\left(3+x-y\right)\)
c, \(=x\left(y-z\right)-\left(z-y\right)=\left(x+1\right)\left(y-z\right)\)
a,3xy+x+15y+5
<=> x(3y+1)+5(3y+1)
<=>(3y+1)(x+5)
<=>\(\left[{}\begin{matrix}y=\dfrac{-1}{3}\\y=-5\end{matrix}\right.\)
b, =9−(x−y)\(^2\)
=3\(^2\)-(x−y)\(^2\)
=(3−x+y)(3+x−y)