a, \(6x+6+4x+8+3x+9=12+6x\Leftrightarrow7x=-11\Leftrightarrow x=-\dfrac{11}{7}\)
b, đk : x khác 1 ; -1
\(\dfrac{x^2+2x+1-x^2+2x-1}{x^2-1}=\dfrac{x^2-1-\left(x^2-2x+1\right)}{\left(x+1\right)\left(x-1\right)}\)
\(\Leftrightarrow4x=2x-2\Leftrightarrow x=-1\left(ktm\right)\)
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