a) \(\left(x-\frac{1}{2}\right)^4=\frac{1}{81}\)
\(\Rightarrow\left(x-\frac{1}{2}\right)^4=\left(\frac{1}{3}\right)^4\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{2}=\frac{1}{3}\\x-\frac{1}{2}=\frac{-1}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{5}{6}\\x=\frac{1}{6}\end{cases}}\)
Vậy ...
b) ta có: \(5^{50}=\left(5^2\right)^{25}=25^{25}\); \(3^{75}=\left(3^3\right)^{25}=27^{25}\).
Mà \(25^{25}< 27^{25}\)nên \(5^{50}< 3^{75}\)
#)Giải :
a) \(\left(x-\frac{1}{2}\right)^4=\frac{1}{81}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)^4=\left(\frac{1}{3}\right)^4\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{5}{6}\)
b) Ta có :
\(5^{50}=\left(5^2\right)^{25}=25^{25}\)
\(3^{75}=\left(3^3\right)^{25}=27^{25}\)
Vì \(25^{25}< 27^{25}\Rightarrow5^{50}< 3^{75}\)
b,5\(^{50}\)và 3\(^{75}\)
5\(^{50}\)=(5\(^2\))\(^{25}\)=25\(^{25}\)
3\(^{75}\)=(3\(^3\))\(^{25}\)=27\(^{25}\)
=>25\(^{25}\)< 27\(^{25}\)
vậy 5\(^{50}\)< 3\(^{75}\)
a,(x-1/2)^4=1/18
=>(x-1/2)^4=(1/3)^4 hoặc (x-1/2)^4=(-1/3)^4
=>x-1/2=1/3 hoặc x-1/2=-1/3
=>x=5/6 hoặc x=1/6
vậy........../
......học tốt...;.