\(M=1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+....+\frac{1}{2^{2016}}\)
\(\Rightarrow\)\(2M=2+1+\frac{1}{2}+\frac{1}{2^2}+....+\frac{1}{2^{2015}}\)
\(\Rightarrow\)\(2M-M=\left(2+1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2015}}\right)-\left(1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2016}}\right)\)
\(\Rightarrow\)\(M=2-\frac{1}{2^{2016}}< 2\)
Vậy M < 2
cho M =1/1^2+1/2^2+1/3^2+...+1/10^2 so sanh M voi 4/3
cho M= 1/12+1/22+1/32+....+1/102. hay so sanh M voi 1^1/3
Cho M=1+1/2+1/2^2+...+1/2^2015+1/2^2016. so sanh M voi 2
Cho M=\(\frac{1}{1^2}+\frac{1}{2^2}+\frac{1}{3^2}+...+\frac{1}{10^2}\).Hay so sanh M voi \(1\frac{1}{3}\)
hay so sanh m voi 1
M=\(\frac{1}{2!}+\frac{2}{3!}++......+\frac{9}{10!}\)
so sanh : 1/2 + 1/2^2 + 1/2^3 + 1/2^2011 voi 1 - 1/2^2010
A=(1/2^2-1) * (1/3^2-1) *...*(1/100^2-1) so sanh A voi 2
A=(1/2^2-1) * (1/3^2-1) *...*(1/100^2-1) so sanh A voi 1/2
so sanh A= 1/2^2 + 1/ 3^2 +1/4^2+...+ 1/300^2 voi 3/4
