Question

^{_{\(\left|x+\dfrac{1}{2}\right|-\dfrac{2}{5}=0\)}}

Answer 1

\(\left|x+\dfrac{1}{2}\right|-\dfrac{2}{5}=0\)

\(\Rightarrow\left|x+\dfrac{1}{2}\right|=\dfrac{2}{5}\)

\(\Rightarrow x+\dfrac{1}{2}=\pm\dfrac{2}{5}\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{2}{5}\\x+\dfrac{1}{2}=-\dfrac{2}{5}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{10}\\x=-\dfrac{9}{10}\end{matrix}\right.\)

Vậy..............

Answer 2

\(\left|x+\dfrac{1}{2}\right|-\dfrac{2}{5}=0\)

\(\left|x+\dfrac{1}{2}\right|=\dfrac{2}{5}\)

=> \(x+\dfrac{1}{2}=\dfrac{2}{5}\) Hoặc \(x+\dfrac{1}{2}=\dfrac{-2}{5}\)

Với : \(x+\dfrac{1}{2}=\dfrac{2}{5}\)

=> \(x=\dfrac{2}{5}-\dfrac{1}{2}\)

\(x=\dfrac{-1}{10}\)

Với : \(x+\dfrac{1}{2}=\dfrac{-2}{5}\)

\(x=\dfrac{-2}{5}-\dfrac{1}{2}\)

\(x=\dfrac{-9}{10}\)

Answer 3

Vì |x+\(\dfrac{1}{2}\)|-\(\dfrac{2}{5}\)=0

Nên x hoặc -x

X=\(\dfrac{2}{5}-\dfrac{1}{2}\)=\(\dfrac{4}{9}\)

=>x=\(\dfrac{4}{9}\)hoặc\(\dfrac{-4}{9}\)

Answer 4

\(\left|x+\dfrac{1}{2}\right|-\dfrac{2}{5}=0\)

\(\left|x+\dfrac{1}{2}\right|=0+\dfrac{2}{5}\)

\(\left|x+\dfrac{1}{2}\right|=\dfrac{2}{5}\)

=> \(x+\dfrac{1}{2}=\dfrac{2}{5}\) hoặc \(x+\dfrac{1}{2}=-\dfrac{2}{5}\)

=> \(x=\dfrac{2}{5}-\dfrac{1}{2}\) hoặc \(x=-\dfrac{2}{5}-\dfrac{1}{2}\)

=> \(x=-\dfrac{1}{10}\) hoặc \(x=-\dfrac{9}{10}\)