Question

\(\left|x-2016\right|^{2015}+\left|y+2015\right|^{2016}\)     be hon hoac bang 0

Answer 1

TA CÓ:

\(\hept{\begin{cases}\left|x-2016\right|\ge0\Rightarrow\left|x-2016\right|^{2015}\ge0\\\left|y+2015\right|\ge0\Rightarrow\left|y+2015\right|^{2016}\ge0\end{cases}}.\)

Vậy\(\left|x+2016\right|^{2015}+\left|y+2016\right|^{2015}\ge0\)

Answer 2

be hon hoac bang ko ms dung ban a minh ghi nham