nếu tìm x thì nó bằng 1 vì cơ số là 1-1=0 mà cơ số bằng 0 thì mũ mấy cũng bằng 1 thôi
ax = ay => x = y
x+2 = x+4 vn
0n = 0
x-1 = 0
x = 1
1m = 1n
x-1 = 1
x = 2
kl: x = 1;2
nếu tìm x thì nó bằng 1 vì cơ số là 1-1=0 mà cơ số bằng 0 thì mũ mấy cũng bằng 1 thôi
ax = ay => x = y
x+2 = x+4 vn
0n = 0
x-1 = 0
x = 1
1m = 1n
x-1 = 1
x = 2
kl: x = 1;2
Tìm x biết
1) \(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
2)\(\left(8x-3\right)\left(3x+2\right)-\left(4x+7\right)\left(x+4\right)=\left(2x+1\right)\left(5x+1\right)-33\)
3)\(6x\left(3x+5\right)-2x\left(9x-2\right)+\left(17-x\right)\left(x-1\right)+x\left(x-18\right)-17x^2=0\)
4)\(\left(x-1\right)\left(x+2\right)-\left(x-3\right)+5x-7=0\)
Giúp mình nha. Camon nhiều
RÚT GỌN
\(a)\)\(\left(x-5\right)\left(x+8\right)-\left(x+4\right)\left(x-1\right)\)
\(b)\)\(x^4\left(x^2-1\right)\left(x^2+1\right)\)
\(c)\)\(\left(x+2\right)\left(x^2-2x+4\right)-\left(x-1\right)\left(x^2+x+1\right)\)
Tìm x biết :
1. \(\left|2x-1\right|=1-2x\)
2. \(\left|x-1\right|+\left|x-2\right|=1\)
3. \(\left|x+1\right|+\left|x+2\right|=3\)
4. \(\left|x+2\right|+\left|x+3\right|=4\left(x-1\right)-\left|x-1\right|\)
5. \(\left|x+2\right|+\left|x+3\right|=4\left(x+1\right)-\left|x-1\right|\)
Các bạn trình bày cách giải, đúng thì mik tick cho nhé
Chứng minh rằng:\(x^{\left(2^{y+1}\right)}+x^{\left(2^y\right)}+1=\left(x^2+x+1\right)\left(x^2-x+1\right)\left(x^4-x^2+1\right)...\left(x^{\left(2^{y-1}\right)}+x^{\left(2^{y-2}\right)}+1\right)\left(x^{\left(2^y\right)}+x^{\left(2^{y-1}\right)}+1\right)\)với mọi \(x\in N;x>0\)và \(y\in N;y>1\)
Tìm x biết:
\(\left|x+1\right|+\left|x+2\right|+\left|x+3\right|+\left|x+4\right|=5x-1\)-1
\(\left|x+1,1\right|+\left|x+1,2\right|+\left|x+1,3\right|+\left|x+1,4\right|=5x\)
\(\left|x+1\right|-\left|3x+2\right|=x+2\)
Tìm x :
\(\left|x-1\right|+\left|x-2\right|+\left|x-3\right|+\left|x-4\right|+\left|2x-5\right|=4\)
\(\left|x+1\right|+\left|x+2\right|+\left|x-1\right|+\left|x-5\right|+\left|3x+2\right|=9\)
Mình đag cần rất gấp. mọi ng giúp mình với
Tìm x biết:
a) \(\left|x+2\dfrac{1}{2}\right|=\left|3x+1\right|\)
b) \(\left|2x-6\right|+\left|x+3\right|=8\)
c) \(2.\left|x+2\right|+\left|4-x\right|=11\)
TÍNH
a.\(-\dfrac{5}{4}x^4.\dfrac{8}{15}x\) b.\(-2x\left(\dfrac{3}{4}x^2-x+\dfrac{1}{2}\right)\) c.\(x\left(x-\dfrac{1}{2}\right)-\left(x-2\right)\left(x+3\right)\)
C=\(x\)\(\left[x^2-y\right]\)x\(\left[x^3-2y^2\right]\)x\(\left[x^4-3y^3\right]\)x\(\left[x^5-4y^4\right]\)tại \(x=2,y=-2\)
D=\(x^2\left[x+y\right]\)-\(y^2\)\(\left[x+y\right]\)+\(\left[x^2-y^2\right]\)+2\(\left[x+y\right]\)+3 biết rằng x+y+1=0
M=\(\left[x+y\right]\)x\(\left[y+z\right]\)x\(\left[x+z\right]\)biết ranhwfx+y+z=xyz=2
Bài 4 : Tìm \(x\), biết :
a ) \(\left|4-2x\right|+\left|x+3\right|=8\)
b ) \(\left|x+1\right|+\left|x-2\right|+\left|x+3\right|=6\)
c ) \(\left|x-2\right|+\left|x-3\right|+\left|4-x\right|=2\)
d ) \(2\left|x+2\right|+\left|4-3x\right|=11\)
e ) \(\left|2x-1\right|+\left|2x-5\right|=4\)
g ) \(\left|x-3\right|+\left|3x+4\right|=\left|2x+1\right|\)