Question

\(\left(\left(x+32\right)-17\right)\cdot2=42\)

Answer 1

[ ( x + 32 ) - 17 ] . 2 = 42

[ ( x + 32 ) - 17 ]      = 42 : 2

[ ( x + 32 ) - 17 ]      = 21

  ( x + 32 )               = 21 + 17

     x + 32                = 38

     x                        = 38 - 32

     x                        = 6

Vậy x = 6

Answer 2

  ((x + 32) - 17 .2 = 42

<=>  ( x + 32) - 17 = 42 : 2

<=> (x + 32) - 17 = 21

<=> x + 32 = 17 + 21

<=> x + 32 = 38

<=> x = 38 - 32

<=> x = 6

Answer 3

   ((x+32)-17).2=42

=>(x+32)-17    =42:2=21

=>x+32            =21+17=38

=>x                  =38-32=6