Question

\(\left[\left(\frac{2}{1001}-\frac{3}{2002}\right).\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{1008}+\frac{11}{2016}\right).\frac{1008}{25}+\frac{1009}{2016}\right]\)

        giải hộ vs :((( tỉ mỉ nha ! 

Lm đúng mk tick cho 

Answer 1

\(\left[\left(\frac{2}{1001}-\frac{3}{2002}\right).\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{1008}+\frac{11}{2016}\right).\frac{1008}{25}+\frac{1009}{2016}\right]\)

\(=\left[\left(\frac{4}{2002}-\frac{3}{2002}\right).\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{14}{2016}+\frac{11}{2016}\right).\frac{1008}{25}+\frac{1009}{2016}\right]\)

\(=\left(\frac{1}{2002}.\frac{1001}{17}+\frac{33}{34}\right):\left(\frac{25}{2016}.\frac{1008}{25}+\frac{1009}{2016}\right)\)

\(=\left(\frac{1}{34}+\frac{33}{34}\right):\left(\frac{1}{2}+\frac{1009}{2016}\right)\)

\(=1:\frac{2017}{2016}\)

\(=\frac{2016}{2017}\)

Answer 2

Câu này bạn có thể áp dụng phương pháp phân phối để rút gọn các phân số cho dễ nhé. Còn bạn cũng có thể áp dụng cách quy đồng cũng ko sai. Sorry bn nhé mình đang bận nên ko trình bày rõ đc ạ

Answer 3

\(\left[\left(\frac{2}{1001}-\frac{3}{2002}\right).\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{1008}+\frac{11}{2016}\right).\frac{1008}{25}+\frac{1009}{2016}\right]\)

\(=\left[\frac{1001}{17}.\frac{2}{1001}-\frac{3}{2002}.\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{1008}{25}.\frac{7}{1008}+\frac{1008}{25}.\frac{11}{2016}+\frac{1009}{2016}\right)\right]\)

\(=\left[\frac{2}{17}-\frac{3}{34}+\frac{33}{34}\right]:\left[\frac{7}{25}+\frac{11}{50}+\frac{1009}{2016}\right]\)

\(=\left[\frac{2}{17}+\frac{15}{17}\right]:\left[\frac{14}{50}+\frac{11}{50}+\frac{1009}{2016}\right]\)

\(=1:\left[\frac{1}{2}+\frac{1009}{2016}\right]\)

\(=1:\left[\frac{1008}{2016}+\frac{1009}{2016}\right]\)

\(=1:\frac{2017}{2016}\)

\(=\frac{2016}{2017}\)

Học tốt nha!!!

Answer 4

[(10012​−20023​).171001​+3433​]:[(10087​+201611​).251008​+20161009​]

=\left[\frac{1001}{17}.\frac{2}{1001}-\frac{3}{2002}.\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{1008}{25}.\frac{7}{1008}+\frac{1008}{25}.\frac{11}{2016}+\frac{1009}{2016}\right)\right]=[171001​.10012​−20023​.171001​+3433​]:[(251008​.10087​+251008​.201611​+20161009​)]

=\left[\frac{2}{17}-\frac{3}{34}+\frac{33}{34}\right]:\left[\frac{7}{25}+\frac{11}{50}+\frac{1009}{2016}\right]=[172​−343​+3433​]:[257​+5011​+20161009​]

=\left[\frac{2}{17}+\frac{15}{17}\right]:\left[\frac{14}{50}+\frac{11}{50}+\frac{1009}{2016}\right]=[172​+1715​]:[5014​+5011​+20161009​]

=1:\left[\frac{1}{2}+\frac{1009}{2016}\right]=1:[21​+20161009​]

=1:\left[\frac{1008}{2016}+\frac{1009}{2016}\right]=1:[20161008​+20161009​]

=1:\frac{2017}{2016}=1:20162017​

=\frac{2016}{2017}=20172016​