\(\left\lbrack36.4-4.\left(82-7.11\right)^2:4\right\rbrack.2016^0\)
\(=\left\lbrack144-4.\left(82-77\right)^2:4\right\rbrack.1\)
\(=\left\lbrack144-4.5^2:4\right\rbrack\)
\(=\left\lbrack144-4.25:4\right\rbrack\)
\(=144-100:4\)
\(=144-25\)
\(=119\)
\(\left\lbrack36.4-4.\left(82-7.11\right)^2:4\right\rbrack.2016^0\)
\(=\left\lbrack144-4.\left(82-77\right)^2:4\right\rbrack.1\)
\(=\left\lbrack144-4.5^2:4\right\rbrack\)
\(=\left\lbrack144-4.25:4\right\rbrack\)
\(=144-100:4\)
\(=144-25\)
\(=119\)
Tính
\(17^0+\left[5^{13}:5^{11}+\left(135-130\right)^3\right]\)
\(\left[36\cdot4-4\left(82-7\cdot11\right)^2:4\right]-2016\)
Chứng minh rằng:
a,\(\frac{5}{3.7}+\frac{5}{7.11}+\frac{5}{11.15}+...+\frac{5}{\left(4n-1\right).\left(4n+3\right)}=\frac{5n}{3.\left(4n+3\right)}\)
b,\(\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+100}< \frac{1}{4}\)
a,\(3-\left(\frac{-6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)
b,\(\left(-2\right)^3+2^2+\left(-1\right)^{20}+\left(-2\right)^0\)
c,\(\left(\left(3\right)^2\right)^2-\left(\left(-5\right)^2\right)^2-\left(\left(-2\right)^3\right)^2\)
d,\(2^4+8[\left(-2\right)^2:\frac{1}{2}]^0-2^{-2}.4+\left(-2\right)^2\)
e, \(2^3+3\left(\frac{1}{2}\right)^0-2^{-2}.4+[\left(-2\right)^2:\frac{1}{2}].8\)
36.4 -4 . ( 82 -7.11) \(^2\) : 4- 2016 \(^0\)
Thực hiện phép tính:
1, \(\left(\dfrac{-1}{2}\right)^2.\left|+8\right|-\left(-\dfrac{1}{2}\right)^3:\left|-\dfrac{1}{16}\right|\)
2, \(\left|-0,25\right|-\left(-\dfrac{3}{2}\right)^2:\dfrac{1}{4}+\dfrac{3}{4}.2017^0\)
3, \(\left|\dfrac{2}{3}-\dfrac{5}{6}\right|.\left(3,6:2\dfrac{2}{5}\right)^3\)
4, \(\left|\left(-0,5\right)^2+\dfrac{7}{2}\right|.10-\left(\dfrac{29}{30}-\dfrac{7}{15}\right):\left(-\dfrac{2017}{2018}\right)^0\)
5, \(\dfrac{8}{3}+\left(3-\dfrac{1}{2}\right)^2-\left|\dfrac{-7}{3}\right|\)
a) \(-7\left(5-x\right)-2\left(x-10\right)=15\)
b) \(4\left(2-x\right)+3\left(x-5\right)=14\)
c) \(-5\left(2-x\right)+4\left(x-3\right)=10x-15\)
d) \(-7\left(3x-5\right)+2\left(7x-14\right)=28\)
e) \(5\left(4-x\right)-7\left(-x+2\right)=4-9+3\)
f) \(5\left(x-7\right)+10\left(3-x\right)=20\)
g) \(-4\left(x+1\right)+8\left(x-3\right)=24\)
h) \(4\left(x-1\right)-3\left(x-2\right)=-|-5|\)
Giúp mình với, AI NHANH NHẤT MÌNH CHO Ờ NGHEN!
\(\dfrac{-5}{2}-\left(\dfrac{-7}{2}-\dfrac{7}{4}\right):\left(\dfrac{-7}{3}\right)-\left(\dfrac{-7}{3}\right)-\left(2021\right)^0\)
a) \(\left(x^2-5\right).\left(x^2-25\right)< 0\)
b) \(\left(x+5\right).\left(9+x^2\right)< 0\)
c) \(\left(x+3\right).\left(x^2+1\right)=0\)
d) \(\left(x+5\right).\left(x^2-4\right)=0\)
\(\left(x-1\right)\left(x+1\right)+2=0\)
\(\left(x+1\right).\left(3-x\right)=0\)
\(\left(2-x\right)^4=81\)
\(\left(x^2+1\right).\left(81-x^2\right)=0\)