Question

\(\left(\frac{3}{4}-\frac{5}{6}\right)^2\)

Answer 1

\(\left(\frac{3}{4}-\frac{5}{6}\right)^2=\left[\frac{3}{4}+\left(-\frac{5}{6}\right)\right]^2=\left(\frac{18+\left(-20\right)}{24}\right)^2=\left(-\frac{2}{24}\right)^2=\left(-\frac{1}{12}\right)^2=\frac{1}{144}\)

Answer 2

\(\left(\frac{3}{4}-\frac{5}{6}\right)^2=\left(\frac{9-10}{12}\right)^2=\left(-\frac{1}{12}\right)^2=\frac{1}{144}\)

Answer 3

\(=\left(-\frac{1}{12}\right)^2\)

\(=-\frac{1}{12}\cdot-\frac{1}{12}\)

\(=\frac{1}{144}\)

Answer 4

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Answer 5

\(\left(\frac{3}{4}-\frac{5}{6}\right)^2=\left(\frac{9}{12}-\frac{10}{12}\right)^2=\frac{-1}{12}^2=\frac{1}{144}\)

Answer 6

\(\left(\frac{3}{4}-\frac{5}{6}\right)^2=\left(\frac{9}{12}-\frac{10}{12}\right)^2=\left(\frac{-1}{12}\right)^2=\frac{1}{144}\)

Answer 7

\(=\left(\frac{9}{12}-\frac{10}{12}\right)^2\)

\(=\left(\frac{-1}{12}\right)^2\)

\(=\frac{1}{24}\)