Question

\(\left(\frac{2}{3}-1\frac{1}{2}\right):\frac{4}{3}+\frac{1}{2}\)

Giúp mình nha. Cảm ơn nhiều !

Answer 1

\(\left(\frac{2}{3}-1\frac{1}{2}\right):\frac{4}{3}+\frac{1}{2}\)

=\(\left(\frac{2}{3}-\frac{3}{2}\right)\times\frac{3}{4}+\frac{1}{2}\)

=\(\frac{-5}{6}\times\frac{3}{4}+\frac{1}{2}\)

=\(\frac{-5}{8}+\frac{4}{8}\)

=\(\frac{-1}{8}\)

Ai thấy đúng thì *******

Answer 2

\(\left(\frac{2}{3}-1\frac{1}{2}\right):\frac{4}{3}+\frac{1}{2}\)

\(=\left(\frac{2}{3}-\frac{3}{2}\right):\frac{4}{3}+\frac{1}{2}\)

\(=\left(\frac{4}{6}-\frac{9}{6}\right):\frac{4}{3}+\frac{1}{2}\)

\(=\frac{-5}{6}:\frac{4}{3}+\frac{1}{2}\)

\(=\frac{-5}{6}.\frac{3}{4}+\frac{1}{2}\)

\(=\frac{-5}{8}+\frac{1}{2}\)

\(=\frac{-5}{8}+\frac{4}{8}\)

\(=\frac{1}{8}\)