Question

\(\left(\frac{1}{17}-1\right)\left(\frac{2}{17}-1\right)\left(\frac{3}{17}-1\right)...\left(\frac{99}{17}-1\right)\)

Answer 1

???????????????????? chúc bạn giả bài này nhé chịu thôi

Answer 2

\(\left(\frac{1}{17}-1\right)\left(\frac{2}{17}-1\right)\left(\frac{3}{17}-1\right)....\left(\frac{99}{17}-1\right)\)

= \(\left(\frac{1}{17}-\frac{17}{17}\right)\left(\frac{2}{17}-\frac{17}{17}\right)\left(\frac{3}{17}-\frac{17}{17}\right).......\left(\frac{99}{17}-\frac{17}{17}\right)\)

= \(\left(\frac{-16}{17}\right)\left(\frac{-15}{17}\right)\left(\frac{-14}{17}\right).......\left(\frac{82}{17}\right)\)

= \(\frac{\left(-16\right).\left(-15\right).\left(-14\right)......82}{17}\)