Question

\(\left(7^{2003}+7^{2002}\right):\left(7^{2001}.7\right)\)

Answer 1

\(\left(7^{2003}+7^{2002}\right):\left(7^{2001}.7\right)\)

\(=\left(7^{2003}+7^{2002}\right):7^{2002}\)

\(=7^{2003}:7^{2002}+7^{2002}:7^{2002}\)

\(=7^{2003}:7^{2002}+1\)

\(=7^{2002}.7:7^{2002}.1+1\)

\(=7^{2002}.\left(7-1\right)+1\)

\(=7^{2002}.6+1\)

Answer 2

Ta có: \(\left(7^{2003}+7^{2002}\right):\left(7^{2001}.7\right)\)

\(\Rightarrow\left(7^{2003}+7^{2002}\right):7^{2002}\)

\(\Rightarrow7^{2002}:7^{2003}+7^{2002}:7^{2002}\)

Tự tính tiếp nha

Answer 3

=(7^2002*7+7^2002*1):(7^2002)

=7^2002*8:7^2002

=8