Question

\(\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{2017}\right)\)

Answer 1

\(\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right)...\left(1+\frac{1}{2017}\right)\)

\(=\frac{3}{2}.\frac{4}{3}....\frac{2018}{2017}\)

\(=\frac{3.4....2018}{2.3....2017}=\)\(\frac{2018}{2}=1009\)

Answer 2

=\(\frac{3}{2} × \frac{4}{3} × \frac{5}{4} ....× \frac{2018}{2017}\)

=>2008/2 = 1004

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