Question

\(\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}-\left(-1\right)=\frac{1}{3}\)

đề : tìm x

Answer 1

\(\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}-\left(-1\right)=\frac{1}{3}\)

\(\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}+1=\frac{1}{3}\)

\(\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}=\frac{1}{3}-1\)

\(\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}=\frac{-2}{3}\)

\(-0,6x-\frac{1}{2}=-\frac{2}{3}:\frac{3}{4}\)

\(-0,6x=-\frac{8}{9}\)

\(x=\frac{-8}{9}:\left(-0,6\right)\)

\(x=\frac{40}{27}\)

Answer 2

@SKT_NTT cảm ơn bn

Answer 3

cảm ơn jma cụt ngủn Nguyễn Lan Anb