a)1+2+3+...+n
=[(n-1):1+1].(n+1):2
=n.( n+1)/2
b) {[(2n-1)-1]:2+1}. [(2n-1)+1]:2
=n.n=n2
a) 1+2+3+...+n
= [(n-1):1+1].(n+1):2
= n.( n+1)/2
b) {[(2n-1)-1]:2+1}. [(2n-1)+1]:2
= n.n = n2
a) 1 + 2 + 3 +...+ n
= [( n - 1 ) : 1 + 1 ] . ( n + 1 ) : 2
= n . ( n + 1 )/2
b) 1 + 3 + 5 + 7 +...+ ( 2n - 1 )
= {[( 2 n - 1 ) - 1 ] : 2 + 1 } . [( 2 n - 1 ) + 1 ] : 2
= n . n = n2
Hk tốt