Vì :
|x + 2| ≥ 0
|x + 5| ≥ 0
|x + 9| ≥ 0
|x + 11| ≥ 0
=> |x + 2| + |x + 5| + |x + 9| + |x + 11| ≥ 0
Hay 5x ≥ 0 => x ≥ 0
=> |x + 2| + |x + 5| + |x + 9| + |x + 11| = x + 2 + x + 5 + x + 9 + x + 11
= 4x + 27 = 5x
=> x = 27
Vậy x = 27
HAPPY NEW YEAR !!!
Ta có :
\(\left|x+2\right|\ge0\)
\(\left|x+5\right|\ge0\)
\(\left|x+9\right|\ge0\)
\(\left|x+2\right|\ge0\)
[x + 2 ] + [ x + 5 ] [ x + 9 ] + [ x + 11 ] = 5x
x . 4 + ( 2 + 5 + 9 + 11 ) = 5x
x . 4 + 17 = 5x
Từ đây bạn làm tiếp nha
Ta có :
\(\left|x+2\right|\ge0\)
\(\left|x+5\right|\ge0\)
\(\left|x+9\right|\ge0\)
\(\left|x+11\right|\ge0\)
\(\Rightarrow5x\ge0\)
Mà 5 > 0
=> \(x\ge0\)
=> |x + 2| + |x + 5| + |x + 7| + |x + 11| = 5x
=> x + 2 +x + 5 + x + 7 + x + 11 = 5x
=> 4x + 25 = 5x
=> 5x - 4x = 25
=> x = 25